class Root
{
public static void main(String[] args)
{
int d=0;
double r1=0,r2=0;
int a=Integer.parseInt(args[0]);
int b=Integer.parseInt(args[1]);
int c=Integer.parseInt(args[2]);
d=((b*b)-(4*a*c));
if(d==0)
{
System.out.println("roots are real and equal");
r1=(-b)/(2*a);
r2=(-b)/(2*a);
System.out.println(r1);
System.out.println(r2);
}
else if(d>0)
{
System.out.println("roots are real and distinct");
r1=(-b+Math.sqrt(d))/(2*a);
r2=(-b-Math.sqrt(d))/(2*a);
System.out.println(r1);
System.out.println(r2);
}
else
{
System.out.println("no real solutions");
}
}
}
PROCEDURE:- 1.enter values for u,a,t to find distance 2.find distance with the formulae ut+1/2at 2 3.print the above result CODE:- #include<stdio.h> #include<conio.h> void main() { float u,t,a,S; clrscr(); printf(“enter values u,t,a”); scanf(“%f %f %f”, &u,&t,&a); S=(u*t)+(0.5*a*t*t); printf(“\n S = %f”, S); } Input:- enter values u,t,a U=10,t=4,a=4.9 Output:- S =79.200
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