class Mat
{
public static void main(String args[])
{
int j,l=0,i;
int a[][]=new int[2][2];
int b[][]= new int[2][2];
for(i=0;i<2;i++)
for(j=0;j<2;j++)
a[i][j]=Integer.parseInt(args[l++]);
for(i=0;i<2;i++)
for(j=0;j<2;j++)
b[i][j]=Integer.parseInt(args[l++]);
for( i=0;i<2;i++)
for( j=0;j<2;j++)
{
int c[][]={{0,0},{0,0}};
for(int k=0;k<2;k++)
{
c[i][j]=c[i][j]+(a[i][k]*b[k][j]);
}
System.out.println(c[i][j]);
}
}
}
PROCEDURE:- 1.enter values for u,a,t to find distance 2.find distance with the formulae ut+1/2at 2 3.print the above result CODE:- #include<stdio.h> #include<conio.h> void main() { float u,t,a,S; clrscr(); printf(“enter values u,t,a”); scanf(“%f %f %f”, &u,&t,&a); S=(u*t)+(0.5*a*t*t); printf(“\n S = %f”, S); } Input:- enter values u,t,a U=10,t=4,a=4.9 Output:- S =79.200
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