Swap Two numbers (without using temporary variable)

PROCEDURE:-

      1.input values for a and b
      2. compute a= a+b
      3. compute b =a-b
      4. compute a=a-b
      5.print value of a and b after swapping

CODE:-

#include<stdio.h>
void main()
{
  int a,b,t;
  printf(“enter value for a,b”);
  scanf(“%d %d”,&a,&b);
  printf(“before swapping  a=%d   b=%d”,a,b);
  a=a+b;
  b=a-b;
  a=a-b;
  printf(“after swapping  a=%d    b=%d”,a,b);
}


Input:- enter value for a,b
                a=5,   b=6
Output:- after swapping  a=6   b=5